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Current Question (ID: 10667)

Question:
$\text{Hypo on treatment with I}_2 \text{ gives:}$
Options:
  • 1. $\text{Na}_2\text{SO}_4$
  • 2. $\text{Na}_2\text{S}_4\text{O}_6$ (Correct)
  • 3. $\text{Na}_2\text{SO}_3$
  • 4. $\text{Na}_2\text{S}$
Solution:
$\text{Hint: Oxidizing action of I}_2$ $\text{Explanation:}$ $\text{STEP 1: Hypo or sodium thiosulphate (2Na}_2\text{S}_2\text{O}_3\text{) on treatment with iodine produces sodium tetrathionate. The reaction is as follows:}$ $2\text{Na}_2\text{S}_2\text{O}_3 + \text{I}_2 \rightarrow \text{Na}_2\text{S}_4\text{O}_6 + 2\text{NaI}$ $\text{STEP 2: Hypo is used for both film and photographic paper processing, the sodium thiosulfate is known as a photographic fixer, and is often referred to as 'hypo', from the original chemical name, hyposulphite of soda.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}