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Current Question (ID: 10672)

Question:

$\text{The partial hydrolysis of one mole of peroxodi-sulphuric acid produces}$

Options:

1. $\text{Two moles of sulphuric acid}$
2. $\text{Two moles of peroxomono-sulphuric acid}$
3. $\text{One mole of sulphuric acid, one mole of peroxomono-sulphuric acid}$ (Correct)
4. $\text{One mole of sulphuric acid, one mole of peroxomono-sulphuric acid and one mole of hydrogen peroxide}$

Solution:

$\text{Hint: Peroxodi-sulphuric acid is } \text{H}_2\text{S}_2\text{O}_8$ $\text{Peroxodisulphuric acid } (\text{H}_2\text{S}_2\text{O}_8) \text{ on complete hydrolysis give to a molecule of } \text{H}_2\text{SO}_4 \text{ and one mole of } \text{H}_2\text{O}_2\text{.}$ $\text{While on partial hydrolysis it gives one mole of peroxomonosulphuric acid and one mole of } \text{H}_2\text{SO}_4\text{. The reaction is as follows:}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}