Import Question JSON

Current Question (ID: 10680)

Question:

$\text{Select the correct option based on the statements below:}$ $\text{Assertion (A): NaCl reacts with concentrated H}_2\text{SO}_4 \text{ to give colourless fumes with a pungent smell. But on adding MnO}_2\text{, the fumes become greenish-yellow.}$ $\text{Reason (R): MnO}_2 \text{ oxidizes HCl to chlorine gas which is greenish-yellow.}$

Options:

1. $\text{Both (A) and (R) are True and (R) is the correct explanation of (A).}$ (Correct)
2. $\text{Both (A) and (R) are True but (R) is not the correct explanation of (A).}$
3. $\text{(A) is True but (R) is False.}$
4. $\text{(A) is False but (R) is True.}$

Solution:

$\text{HINT: Colourless fumes with a pungent smell gas is HCl}$ $\text{Explanation:}$ $\text{NaCl reacts with concentrated H}_2\text{SO}_4 \text{ to give colourless fumes with a pungent smell.}$ $\text{The pungent smell is due to the formation of HCl. The reaction is as follows:}$ $\text{NaCl} + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + 2\text{HCl}$ $\text{But on adding MnO}_2 \text{ the fumes become greenish-yellow due to the formation of chlorine gas. MnO}_2 \text{ oxidised Cl}^- \text{ into Cl}_2\text{.}$ $\text{The reaction is as follows:}$ $\text{MnO}_2 + 4\text{HCl} \rightarrow \text{MnCl}_2 + 2\text{H}_2\text{O} + \text{Cl}_2$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}