Import Question JSON

Current Question (ID: 10691)

Question:

$\text{Match the interhalogen compounds in Column I with the geometry in Column II and assign the correct code:}$ $\text{Column-I:}$ $\text{(A) XX'}$ $\text{(B) XX'}_3$ $\text{(C) XX'}_5$ $\text{(D) XX'}_7$ $\text{Column-II:}$ $\text{(i) T-shape}$ $\text{(ii) Pentagonal bipyramidal}$ $\text{(iii) Linear}$ $\text{(iv) Square Pyramidal}$

Options:

1. $\text{(A)-(iii), (B)-(i), (C)-(iv), (D)-(ii)}$ (Correct)
2. $\text{(A)-(i), (B)-(iv), (C)-(iii), (D)-(ii)}$
3. $\text{(A)-(iv), (B)-(iii), (C)-(ii), (D)-(i)}$
4. $\text{(A)-(iii), (B)-(iv), (C)-(i), (D)-(ii)}$

Solution:

$\text{Hint: Find the hybridization of the central atom, then find the geometry of the compound.}$ $\text{Explanation:}$ $\text{The example of compounds are as follows:}$ $\text{Step 1: Linear: In a linear model, atoms are connected in a straight line, and a bond angle is simply the geometric angle between two adjacent bonds. A simple triatomic molecule of the type AX}_2\text{ has its two bonding orbitals 180° apart.}$ $\text{XX'- Linear (e.g. ClF, BrF)}$ $\text{Step 2: T-shaped molecular geometry describes the structures of some molecules where a central atom has three ligands. The three atoms bond at 90° angles on one side of the central atom, producing the T shape.}$ $\text{XX'}_3\text{- T-shape (e.g. ClF}_3\text{, BrF}_3\text{)}$ $\text{Step 3: In geometry, a square pyramid is a pyramid having a square base. If the apex is perpendicularly above the center of the square}$ $\text{XX'}_5\text{- Square pyramidal (e.g. BrF}_5\text{ IF}_5\text{)}$ $\text{Step 4: A pentagonal bipyramid is a molecular geometry with one atom at the centre with seven ligands at the corners of a pentagonal bipyramid.}$ $\text{XX'}_7\text{- Pentagonal bipyramidal (e.g. IF}_7\text{)}$

Import JSON File

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}