Import Question JSON

Current Question (ID: 10693)

Question:

$\text{Among the following statements, the correct one(s) is/are:}$

Options:

1. $\text{Neon gas is filled in discharge tubes with characteristic colours.}$
2. $\text{Neon gas is used in beacon lights.}$
3. $\text{Argon along with nitrogen is used in gas-filled electric lamps.}$
4. $\text{All of the above.}$ (Correct)

Solution:

$\text{HINT: Neon gas is used in beacon lights.}$ $\text{Explanation:}$ $\text{STEP 1: Neon is used in lights/bulbs because it is one of the noble gases. One characteristic of these elements is that each atom has a filled electron shell, so the atoms don't react with other atoms and it takes a lot of energy to remove an electron.}$ $\text{STEP 2: Uses of neon gas:}$ $\text{(i) It is mixed with helium to protect electrical equipments from high voltage.}$ $\text{(ii) It is filled in discharge tubes with characteristic colours.}$ $\text{(iii) It is used in beacon lights.}$ $\text{Uses of Argon gas:}$ $\text{(i) Argon along with nitrogen is used in gas-filled electric lamps. This is because Ar is more inert than N.}$ $\text{(ii) It is usually used to provide an inert temperature in a high metallurgical process.}$ $\text{(iii) It is also used in laboratories to handle air-sensitive substances}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}