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Current Question (ID: 10695)

Question:
$\text{A xenon fluoride that does not exist is:}$
Options:
  • 1. $\text{XeF}_4$
  • 2. $\text{XeF}_2$
  • 3. $\text{XeF}_3$ (Correct)
  • 4. $\text{XeF}_6$
Solution:
$\textbf{HINT:} \text{XeF}_3 \text{ does not exist.}$ $\textbf{Explanation:}$ $\textbf{Step 1:} \text{XeF}_2\text{, XeF}_4\text{, and XeF}_6 \text{ are obtained by a direct reaction between Xe and F}_2\text{.}$ $\text{The condition under which the reaction is carried out determines the product.}$ $\text{Xe(g) + F}_2\text{(g)} \xrightarrow{673\text{K, 1 bar}} \text{XeF}_2\text{(s)}$ $\text{(Excess)}$ $\text{Xe(g) + 2F}_2\text{(g)} \xrightarrow{873\text{K, 7 bar}} \text{XeF}_4\text{(s)}$ $\text{(1:5 ratio)}$ $\textbf{Step 2:}$ $\text{Xe(g) + 3F}_2\text{(g)} \xrightarrow{573\text{K, 60-70 bar}} \text{XeF}_6\text{(s)}$ $\text{(1:20 ratio)}$ $\text{From these reactions, we can see that XeF}_2\text{, XeF}_4\text{, and XeF}_6 \text{ can be synthesized under specific conditions, but XeF}_3 \text{ does not exist because it would require an odd number of electrons around the central Xe atom, which is not favorable for noble gas compounds.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}