Import Question JSON

Current Question (ID: 10696)

Question:

$\text{Match the species given in Column I with the shape given in Column II and mark the correct option.}$ $\text{Column I:}$ $\text{A. Its partial hydrolysis does not change oxidation state of central atom.}$ $\text{B. It is used in modern diving apparatus.}$ $\text{C. It is used to provide inert atmosphere for filling electrical bulbs.}$ $\text{D. It's central atom is in sp}^3\text{d}^2\text{ hybridisation.}$ $\text{Column II:}$ $\text{1. He}$ $\text{2. XeF}_6$ $\text{3. XeF}_4$ $\text{4. Ar}$ $\text{Codes:}$

Options:

1. $\text{A-1, B-4, C-2, D-3}$
2. $\text{A-1, B-2, C-3, D-4}$
3. $\text{A-2, B-1, C-4, D-3}$ (Correct)
4. $\text{A-1, B-3, C-2, D-4}$

Solution:

$\textbf{HINT:} \text{He is used in diving apparatus.}$ $\textbf{Explanation:}$ $\text{(A) Partial hydrolysis of XeF}_6 \text{ does not change oxidation state of central atom.}$ $\text{XeF}_2 + 2\text{H}_2\text{O} \rightarrow \text{XeO}_3 + 6\text{HF}$ $\text{In this reaction, Xe maintains +6 oxidation state in both XeF}_6 \text{ and XeO}_3\text{. So A matches with 2.}$ $\text{(B) He is used in modern diving apparatus. Since it is very little soluble in blood, it reduces decompression and causes less discomfort to the diver in breathing. So B matches with 1.}$ $\text{(C) Ar is used to provide inert atmosphere for filling electrical bulbs. So C matches with 4.}$ $\text{(D) Central atom (Xe) of XeF}_4 \text{ is in sp}^3\text{d}^2 \text{ hybridisation and has square planar geometry. So D matches with 3.}$ $\text{Therefore, the correct matching is A-2, B-1, C-4, D-3.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}