Import Question JSON

Current Question (ID: 10700)

Question:

$\text{Which of the following statements is false?}$

Options:

1. $\text{H}_3\text{PO}_2\text{, H}_3\text{PO}_3 \text{ and H}_3\text{PO}_4 \text{ all are tribasic and reducing in nature.}$ (Correct)
2. $\text{Amongst anions } NO_3^-\text{, } SO_3^{2-}\text{, } CO_3^{2-}\text{, and } BO_3^{3-}\text{, only } SO_3^{2-} \text{ have p}\pi\text{-d}\pi \text{ bonding.}$
3. $\text{Amongst anions } SO_3^{2-}\text{, } SO_3^{2-}\text{, } S_2O_4^{2-} \text{ and } HSO_4^-\text{, } SO_3^{2-} \text{ is basic and reducing in nature.}$
4. $\text{Number of lone pair(s) of electrons on Xe atoms in XeF}_2\text{, XeF}_4 \text{ and XeF}_6 \text{ are 3, 2 and 1 respectively.}$

Solution:

$\text{Hint: H}_3\text{PO}_2 \text{ is monobasic}$ $\text{1. Tribasic acid means the acid which can donate three H}^+ \text{ ions. The structures of H}_3\text{PO}_2\text{, H}_3\text{PO}_3 \text{ and H}_3\text{PO}_4 \text{ are as follows:}$ $\text{H}_3\text{PO}_2\text{, H}_3\text{PO}_3 \text{ and H}_3\text{PO}_4\text{, are monobasic, dibasic and tribasic respectively.}$ $\text{2. } SO_3^{2-} \text{ has a double bond between sulphur and oxygen. The }\pi\text{- bond is formed between p orbital of oxygen and d orbital of sulphur.}$ $\text{3. } SO_3^{2-} \text{ contains one lone pair of electrons on the sulphur atom. Sulfite salts and their solutions are mild reducing agents. They liberate SO}_x \text{ gases when acidified.}$ $\text{4. The structure of XeF}_2\text{, XeF}_4 \text{ and XeF}_6 \text{ is as follows:}$ $\text{XeF}_2\text{, XeF}_4 \text{ and XeF}_6 \text{ contains 3, 2, and 1 respectively.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}