Import Question JSON

Current Question (ID: 10713)

Question:

$\text{Choose the incorrect statement among the following regarding noble gases:}$

Options:

1. $\text{Noble gases have weak dispersion forces.}$
2. $\text{Noble gases have large positive values of electron gain enthalpy.}$
3. $\text{Noble gases are sparingly soluble in water.}$
4. $\text{Noble gases have very high melting and boiling points.}$ (Correct)

Solution:

$\text{HINT: Melting point depends on the force of interaction between the atoms.}$ $\text{Explanation:}$ $\text{The general electronic configuration of noble gas elements is } ns^2 np^6 \text{ except He (i.e. } 1s^2\text{).}$ $\text{Noble gases have large positive electron gain enthalpy because the extra electron has to be placed in the next higher principal quantum energy level thereby producing a highly unstable electronic configuration.}$ $\text{Noble gases only have London dispersion forces, so there's very little attraction between water and these noble gases. They still can dissolve, but only very little, because some water molecules will be able to form dipole-induced dipole attractions with the noble gas atom.}$ $\text{Because of weak dispersion forces melting point and boiling points of noble gases are low.}$ $\text{The melting and boiling point (respectively) of noble gas is as follows:}$ $\text{Ne= 24.6 K; Ar= 83.8 K; Kr=115.9 K; Xe=161.3 K; Rn=202 K}$ $\text{He=4.2 K; Ne=27.1 K; Ar=87.2 K; Kr=119.7 K; Xe=165.0 K; Rn=211 K}$ $\text{Hence, option fourth is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}