Import Question JSON

Current Question (ID: 10719)

Question:

$\text{Select the correct option based on statements below:}$ $\text{Assertion (A): Noble gases have the highest ionization energies in their respective periods.}$ $\text{Reason (R): The outermost sub-shell of noble gases in which the electron enters is completely filled.}$

Options:

1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$
3. $\text{(A) is true but (R) is false.}$ (Correct)
4. $\text{Both (A) and (R) are false.}$

Solution:

$\text{HINT: The general electronic configuration of noble gas is } ns^2np^6$ $\text{Explanation:}$ $\text{STEP 1: Ionisation energy is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.}$ $\text{STEP 2: The noble gases except helium } (1s^2) \text{ have completely filled } ns^2np^6 \text{ electronic configuration in their valence shell.}$ $\text{The ionisation enthalpies of these elements are very high because they have stable, filled shell configurations, it is difficult to remove an electron from any of the noble gases.}$ $\text{Hence, Assertion is a true statement but Reason is false.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}