Import Question JSON

Current Question (ID: 10722)

Question:

$\text{The temperature of a body on the Kelvin scale is found to be } x^{\circ} \text{K. When it is measured by a Fahrenheit thermometer, it is found to be } x^{\circ} \text{F, then the value of } x \text{ is:}$

Options:

1. $40$
2. $313$
3. $574.25$ (Correct)
4. $301.25$

Solution:

$\text{Using temperature-conversion formula:}$ $\Rightarrow \frac{C-0^{\circ}}{100-0^{\circ}} = \frac{F-32}{180}$ $\Rightarrow \frac{x-273}{100} = \frac{x-32}{180}$ $\Rightarrow 9x = 5x + 160 + 2457$ $\Rightarrow x = 574.25$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}