Import Question JSON

Current Question (ID: 10784)

Question:

$\text{The temperature of a body falls from } 50°\text{C to } 40°\text{C in 10 minutes. If the temperature of the surroundings is } 20°\text{C, then the temperature of the body after another 10 minutes will be:}$

Options:

1. $36.6°\text{C}$
2. $33.3°\text{C}$ (Correct)
3. $35°\text{C}$
4. $30°\text{C}$

Solution:

\text{Using Newton's law of cooling:} \text{In first case: } \frac{50-40}{10} = K\left[\frac{50+40}{2} - 20\right] \ldots(i) \text{In second case: } \frac{40-\theta_2}{10} = K\left[\frac{40+\theta_2}{2} - 20\right] \ldots(ii) \text{By solving: } \theta_2 = 33.3^\circ\text{C}

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}