Import Question JSON

Current Question (ID: 10792)

Question:

$\text{Two absolute scales } A \text{ and } B, \text{ have triple points of water defined to be } 200A \text{ and } 350B. \text{ The relationship between } T_A \text{ and } T_B\text{:}$

Options:

1. $T_A = \frac{5}{7}T_B$
2. $T_A = \frac{4}{7}T_B$ (Correct)
3. $T_A = \frac{7}{4}T_B$
4. $T_A = T_B$

Solution:

$\text{Hint: The triple point of the water remains the same for two different scales.}$ $\text{Step 1: Find the ratio of the values of the triple point at two scales.}$ $\frac{T_A}{T_B} = \frac{200}{350}$ $T_A = \frac{4}{7}T_B$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}