Import Question JSON

Current Question (ID: 10797)

Question:

$\text{Steam at } 100°\text{C is injected into 20 g of } 10°\text{C water. When water acquires a temperature of } 80°\text{C, the mass of water present will be:}$ $\text{(Take specific heat of water } = 1 \text{ cal g}^{-1} °\text{C}^{-1} \text{ and latent heat of steam } = 540 \text{ cal g}^{-1}\text{)}$

Options:

1. $24 \text{ g}$
2. $31.5 \text{ g}$
3. $42.5 \text{ g}$
4. $22.5 \text{ g}$ (Correct)

Solution:

$\text{Heat lost by steam = Heat gained by water}$ $\text{Let m' amount of steam converts into water.}$ $m' \times L + m's(100-80) = ms\Delta t$ $m' \times 540 + m' \times 20 = 20 \times 1 \times (80-10)$ $m' = 20 \times 70/560 = 2.5\text{g}$ $\text{Now, net water} = 20 + 2.5 = 22.5\text{g}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}