Import Question JSON

Current Question (ID: 10798)

Question:

$\text{When the pressure on the surface of water is increased, its boiling point will:}$

Options:

1. $\text{Decrease}$
2. $\text{Increase}$ (Correct)
3. $\text{Remain same}$
4. $\text{Increase or decrease}$

Solution:

$\text{Hint: At high pressure, molecules come closer and require more heat to boil.}$ $\text{Step 1:}$ $\text{When the pressure on the surface of the water is increased, its boiling point will increase.}$ $\text{Explanation:}$ $\text{The boiling point of a liquid is the temperature at which the vapor pressure of the liquid equals the external pressure. When external pressure increases, the vapor pressure must also increase to reach the boiling point, which requires a higher temperature.}$ $\text{At higher pressures, water molecules are pushed closer together, making it more difficult for them to escape into the vapor phase. Therefore, more thermal energy (higher temperature) is needed to provide enough kinetic energy for the molecules to overcome both the intermolecular forces and the increased external pressure.}$ $\text{This principle is used in pressure cookers, where increased pressure allows water to boil at temperatures higher than 100°C, cooking food faster.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}