Import Question JSON

Current Question (ID: 10816)

Question:

$\text{The correct hybridization states of carbon atoms in the following compound are -}$ $\text{CH}_2 = \text{CH} - \text{C} \equiv \text{N}$

Options:

1. $\text{C}^1 = \text{sp}, \text{C}^2 = \text{sp}^3, \text{C}^3 = \text{sp}^2$
2. $\text{C}^1 = \text{sp}^2, \text{C}^2 = \text{sp}^3, \text{C}^3 = \text{sp}^3$
3. $\text{C}^1 = \text{sp}^2, \text{C}^2 = \text{sp}^2, \text{C}^3 = \text{sp}$ (Correct)
4. $\text{C}^1 = \text{sp}^3, \text{C}^2 = \text{sp}^3, \text{C}^3 = \text{sp}^3$

Solution:

$\text{Hint: Carbon is sp hybridization when two double bonds or one single + one triple bond. two single bonds, one double bond is sp}^2 \text{ hybridized}$ $\text{Step 1: Draw the structure of the molecule}$ $\text{Carbon - sp}^2 \text{ hybridization: A carbon atom bound to three atoms (two single bonds, one double bond) is sp}^2 \text{ hybridized and forms a flat trigonal or triangular arrangement with 120° angles between bonds. Notice that acetic acid contains one sp}^2 \text{ carbon atom and one sp}^3 \text{ carbon atom.}$ $\text{Carbon - sp hybridization: The third possible arrangement for carbon is sp hybridization which occurs when carbon is bound to two other atoms (two double bonds or one single + one triple bond). This hybridization results in a linear arrangement with an angle of 180° between bonds.}$ $\text{CH}_2 = \text{CH} - \text{C} \equiv \text{N}$ $\text{Step 2: Hence, the correct option is 3}$ $\text{C}-1 \text{ is sp}^2 \text{ hybridised.}$ $\text{C}-2 \text{ is sp}^2 \text{ hybridised.}$ $\text{C}-3 \text{ is sp hybridised.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}