Import Question JSON

Current Question (ID: 10821)

Question:

$\text{The number of primary carbon atoms in the following compound are:}$

Options:

1. $6$ (Correct)
2. $2$
3. $4$
4. $3$

Solution:

$\text{Hint: A primary carbon is a carbon atom that is bound to only one other carbon atom.}$ $\text{A primary carbon is one that is attached to one carbon atom. The molecule has 6 primary carbon atoms.}$ $\text{The structure is as follows:}$ $\text{All } \text{CH}_3 \text{ groups are primary carbon.}$ $\text{In the given molecular structure, we can identify that all the methyl groups (}\text{CH}_3\text{) represent primary carbons because each carbon in these groups is bonded to only one other carbon atom. Counting all the }\text{CH}_3\text{ groups in the structure, we find there are 6 primary carbon atoms total.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}