Import Question JSON

Current Question (ID: 10836)

Question:

$\text{Which structure corresponds to the IUPAC name 3-Ethyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid?}$

Options:

1. $\text{Structure with ethyl group at position 3, OH at position 2, methyl at position 4, double bond at position 3, triple bond at position 5, and COOH group}$ (Correct)
2. $\text{Structure with different arrangement of functional groups and carbon chain}$
3. $\text{Structure with alternative positioning of substituents and bonds}$
4. $\text{Structure with modified arrangement of OH, ethyl, and methyl groups}$

Solution:

$\text{Hint: Apply the IUPAC rules for the nomenclature of Polyfunctional groups.}$ $\text{Explanation:}$ $\text{Step 1:}$ $\text{From the name 3-Ethyl-2-hydroxy-4-methylhex-3-en-5-ynoic acid, it is clear that the parent chain contains 6 carbon atoms because \"hex\" indicates six carbon atoms. The numbering should be done in such a way that carboxylic carbon gets the least position.}$ $\text{Step 2:}$ $\text{The parent chain name is hexane. At second position -OH group is present, for -OH group hydroxy is used.}$ $\text{At the third position, an ethyl group is present, and at the fourth position, the methyl group is present.}$ $\text{At the third position double bond is present, for the double bond \"en\" is used. At the fifth position triple bond is present, for the triple bond \"yn\" is used.}$ $\text{Hence, option first is the correct answer. The structure is as follows: a hexanoic acid chain with OH at position 2, ethyl group at position 3, methyl group at position 4, double bond starting at position 3, and triple bond starting at position 5.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}