Import Question JSON

Current Question (ID: 10837)

Question:
$\text{The IUPAC name of the above mentioned compound is -}$
Options:
  • 1. $\text{Citric acid}$
  • 2. $\text{3-Hydroxy pentane-1,5-dioic acid}$
  • 3. $\text{2-Hydroxypropane-1,2,3-tricarboxylic acid}$ (Correct)
  • 4. $\text{2-Carboxy-2-hydroxy propane-1,3-dicarboxylic acid}$
Solution:
$\text{Hint: COOH group carbon did not include in the parent chain.}$ $\text{In the given compound, the parent chain contains three carbon atoms. The acid group carbon did not include in the chain. The structure of a compound with numbering is:}$ $\text{For the COOH group, we use carboxylic acid in the suffix. The molecule contains three COOH groups thus tri is used. At second position -OH group is present for that hydroxy is used. The name of the compound is 2-Hydroxypropane-1,2,3-tricarboxylic acid.}$ $\text{commonly it is known as CITRIC acid.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}