Import Question JSON

Current Question (ID: 10839)

Question:

$\text{The IUPAC name of the above-mentioned compound is:}$

Options:

1. $\text{cis-2-Chloro-3-iodo-2-pentene}$
2. $\text{trans-2-Chloro-3-iodo-2-pentene}$ (Correct)
3. $\text{cis-3-Iodo-4-chloro-3-pentene}$
4. $\text{trans-3-Iodo-4-chloro-3-pentene}$

Solution:

$\text{HINT: Follow IUPAC nomenclature.}$ $\text{The parent chain is having 5 carbon atoms. So, the root name will be pent-.}$ $\text{According to the Lowest sum of locants rule, the numbering will start from the left side because double-bonded carbon gets the lowest position. The configuration of the double bond is trans because higher priority groups are opposite to each other.}$ $\text{Structure analysis: The compound has a 5-carbon chain with a double bond between carbons 2 and 3. Chlorine is attached to carbon 2, and iodine is attached to carbon 3. The ethyl group (CH}_2\text{CH}_3\text{) is also attached to carbon 3.}$ $\text{Since the higher priority groups (Cl and I) are on opposite sides of the double bond, the configuration is trans.}$ $\text{Hence, the IUPAC name of the compound is trans-2-chloro-3-iodo-2-pentene}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}