Import Question JSON

Current Question (ID: 10855)

Question:

$\text{The correct representation involving heterolytic fission of } \text{CH}_3 - \text{Br} \text{ among the following is:}$

Options:

1. $\text{H}_3\text{C} - \text{Br} \rightarrow \text{CH}_3^+ + \text{Br}^-$ (Correct)
2. $\text{H}_3\text{C} - \text{Br} \rightarrow \text{CH}_3^+ + \text{Br}^-$ (Correct)
3. $\text{H}_3\text{C} - \text{Br} \rightarrow \text{CH}_3^- + \text{Br}^+$
4. $\text{H}_3\text{C} - \text{Br} \rightarrow \text{CH}_3 \cdot + \text{Br} \cdot$

Solution:

$\text{Hint: More electronegative element gets negative charge and less electronegative element gets positive charge.}$ $\text{In heterolytic cleavage, unequal distribution of bonding electrons take place. More electronegative element takes bonding electrons and acquire negative charge while less electronegative element acquire positive charge.}$ $\text{Arrow denotes the direction of movement of electrons}$ $\text{Since, Br is more electronegative than carbon, hence heterolytic fission occurs in such a way that } \text{CH}_3 \text{ gets the positive charge and Br gets the negative charge. Thus, option (2) is correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}