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Current Question (ID: 10861)

Question:

$\text{Which of the following is an isomer of ethanol?}$

Options:

1. $\text{Methanol}$
2. $\text{Diethyl ether}$
3. $\text{Acetone}$
4. $\text{Dimethyl ether}$ (Correct)

Solution:

$\text{Hint: Ethanol molecular formula is } \text{CH}_3\text{CH}_2\text{OH}$ $\text{Explanation:}$ $\text{Both ethanol } (\text{C}_2\text{H}_5 \text{OH}) \text{ and dimethyl ether } (\text{CH}_3 \text{OCH}_3) \text{ have the same molecular formula, that is } \text{C}_2\text{H}_6\text{O}\text{. Thus, dimethyl ether is an isomer of ethanol.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}