Import Question JSON

Current Question (ID: 10866)

Question:

$\text{The pair that represents chain isomers is-}$

Options:

1. $\text{CH}_3\text{CHCl}_2$ $\text{and}$ $\text{ClCH}_2\text{CH}_2\text{Cl}$
2. $\text{Propyl alcohol and Isopropyl alcohol}$
3. $\text{2-Methylbutane and Neopentane}$ (Correct)
4. $\text{Diethyl ether and Dipropyl ether}$

Solution:

$\text{Hint: Molecules containing the same parent chain and having the same molecular formula.}$ $\text{When two or more compounds have a similar molecular formula but different carbon skeletons, these are referred to as chain isomers and the phenomenon is termed chain isomerism.}$ $\text{In the first option, both compounds have the same parent chain. Hence, CH}_3\text{CHCl}_2 \text{ and ClCH}_2\text{CH}_2\text{Cl is not an example of chain isomerism.}$ $\text{In the second option, propyl alcohol, and isopropyl alcohol structures are as follows:}$ $\text{Propyl alcohol: HO-CH}_2-\text{CH}_2-\text{CH}_3$ $\text{Isopropyl alcohol: (CH}_3\text{)}_2\text{CH-OH}$ $\text{Both structures have the same parent chain that is propane. Hence, propyl alcohol, and isopropyl alcohol is not an example of chain isomerism.}$ $\text{In the third option, 2-methylbutane and neopentane(IUPAC name: 2,2-dimethylpropane) structures are as follows:}$ $\text{2-Methylbutane: CH}_3-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}_3$ $\text{Neopentane: (CH}_3\text{)}_4\text{C or C(CH}_3\text{)}_4$ $\text{Both compound's molecular formula is the same but the parent chain length is different. Hence, 2-methylbutane and neopentane are chain isomers.}$ $\text{Diethyl ether and Dipropyl ether have different molecular formulas hence, they cannot form isomers.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}