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$\text{Hint: Free radical substitution reaction.}$ $\text{When alkane reacts with } \text{Cl}_2 \text{ then a free radical substitution reaction takes place. All the different type of hydrogen in the compound is replaced by chlorine atoms respectively. In this reaction, multiple products are obtained.}$ $\text{The structure of the given compound are as follows:}$ $\text{The compound is 1,3-dimethylcyclohexane with numbered positions showing symmetry.}$ $\text{Positions (1 \& 5), (2 \& 4) and (6 \& 8) are identical positions due to the symmetry of the molecule.}$ $\text{Therefore, five monochlorinated products can be formed and reactions can occur at positions:}$ $\text{1. Positions (1 \& 5) - equivalent due to symmetry}$ $\text{2. Positions (2 \& 4) - equivalent due to symmetry}$ $\text{3. Positions (6 \& 8) - equivalent due to symmetry}$ $\text{4. Position 3 - unique position}$ $\text{5. Position 7 - unique position}$ $\text{The reaction proceeds as follows:}$ $\text{1,3-dimethylcyclohexane } + \text{Cl}_2/h\nu \rightarrow \text{ 5 different monochlorinated products}$ $\text{Each unique hydrogen environment gives rise to one distinct monochlorinated product, excluding stereoisomers.}$ $\text{Therefore, the total number of monochlorinated products (excluding stereo-isomers) is 5.}$