Import Question JSON

Current Question (ID: 10872)

Question:
$\text{The total number of isomers of } \text{C}_4\text{H}_8 \text{ are-}$
Options:
  • 1. $8$
  • 2. $7$
  • 3. $6$ (Correct)
  • 4. $5$
Solution:
$\text{Hint: Isomers are molecules of the same molecular formula but have a different arrangement of their atoms.}$ $\text{C}_4\text{H}_8 \text{ has 6 isomers. The name of the isomers are as follows:}$ $\text{(1) Cyclobutane}$ $\text{(2) 1-Methylcyclopropane}$ $\text{(3) 1-Butene}$ $\text{(4) cis-2-Butene}$ $\text{(5) trans-2-Butene}$ $\text{(6) 2-Methylpropene}$ $\text{The structures include cyclic compounds (cyclobutane and 1-methylcyclopropane) and alkenes (1-butene, cis-2-butene, trans-2-butene, and 2-methylpropene).}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}