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Current Question (ID: 10874)

Question:

$\text{Total isomers for } \text{C}_4\text{H}_{10}\text{O} \text{ are-}$

Options:

1. $4$
2. $5$
3. $7$
4. $8$ (Correct)

Solution:

$\text{Hint: Include both constitutional and stereoisomers}$ $\text{The constitutional isomers have the same molecular formulas, but they have different connectivities between the atoms.}$ $\text{The constitutional isomers of } \text{C}_4\text{H}_{10}\text{O} \text{ are as follows:}$ $\text{1. butan-1-ol}$ $\text{2. butan-2-ol}$ $\text{3. 2-methylpropan-2-ol}$ $\text{4. 1-methoxypropane}$ $\text{5. ethoxyethane}$ $\text{6. 2-methoxypropane}$ $\text{Total seven constitutional isomers of } \text{C}_4\text{H}_{10}\text{O} \text{ is 7.}$ $\text{In Butan-2-ol, a chiral center is present, thus, it can form two stereoisomers.}$ $\text{So, total 8 isomers are possible.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}