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Current Question (ID: 10875)

Question:
$\text{Geometrical isomerism can be shown by:}$
Options:
  • 1. $\text{Ketone compounds with different positions of functional groups}$
  • 2. $\text{Alkenes with deuterium and hydrogen substituents}$ (Correct)
  • 3. $\text{Resonance structures of carbonic acid}$
  • 4. $\text{Alkyl halides with different chlorine positions}$
Solution:
$\text{Hint: Compounds having the same molecular formula but with different structures are called structural isomers.}$ $\text{Step 1: Analysis of structural isomers}$ $\text{The given compounds have the same molecular formula but they differ in the position of the functional group (ketone group). In structure I, the ketone group is at the C-3 of the parent chain (hexane chain) and in structure II, the ketone group is at the C-2 of the parent chain (hexane chain). Hence, the given pair represents structural isomers.}$ $\text{Step 2: Definition of geometrical isomers}$ $\text{Compounds having the same molecular formula, the same constitution, and the sequence of covalent bonds, but with the different relative positions of their atoms in space are called geometrical isomers.}$ $\text{In structures I and II, the relative position of Deuterium (D) and hydrogen (H) in space are different. Hence, the given pairs represent geometrical isomers.}$ $\text{Analysis of option (c): The given structures are canonical structures or contributing structures. They are hypothetical and individually do not represent any real molecule. Hence, the given pair represents resonance structures, called resonance isomers.}$ $\text{Analysis of option (d): The alkyl halide did not show geometrical isomerism.}$ $\text{Geometrical isomerism requires restricted rotation around a bond (typically a double bond) and different substituents on each carbon of the double bond. Only option 2 shows this with deuterium and hydrogen substituents around a C=C double bond.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}