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Current Question (ID: 10884)

Question:
$\text{The optically active compound among the following is-}$
Options:
  • 1. $\text{Glycerine}$
  • 2. $\text{Acetaldehyde}$
  • 3. $\text{Glyceraldehyde}$ (Correct)
  • 4. $\text{Acetone}$
Solution:
$\text{Hint: Compound must have asymmetric carbon.}$ $\text{Explanation:}$ $\text{Glycerol, acetaldehyde, and acetone don't have asymmetric carbon, that is why they are optically inactive. The glyceraldehyde is optically active because it contains a chiral center.}$ $\text{The structure is as follows:}$ $\text{Glyceraldehyde = 2,3-Dihydroxypropanal}$ $\text{The structure shows a carbon atom (marked with *) bonded to four different groups: -OH, -H, -CHO, and -CH}_2\text{OH, making it a chiral center.}$ $\text{Glycerine = propane-1,2,3-triol}$ $\text{In glycerine, all carbon atoms are bonded to at least two identical groups, so there is no chiral center, making it optically inactive.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}