Import Question JSON

Current Question (ID: 10891)

Question:

$\text{The correct statement regarding electrophile is :}$

Options:

1. $\text{Electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from another electrophile}$
2. $\text{Electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile}$
3. $\text{Electrophiles can be either neutral or positively charged species and can form a bond accepting a pair of electrons from a nucleophile}$ (Correct)
4. $\text{Electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile}$

Solution:

$\text{Hint: Property of electrophile and nucleophile.}$ $\text{Explanation:}$ $\text{Electrophiles can be either neutral or positively charged species and can form a bond by accepting a pair of electrons from a nucleophile.}$ $\text{The neutral electrophile is all Lewis acids: BF}_3\text{, AlCl}_3\text{, SO}_3\text{, ZnCl}_2\text{, BeCl}_2\text{, FeCl}_3\text{, SnCl}_2\text{, CO}_2\text{, SnCl}_4\text{.}$ $\text{The positively charged electrophile is H}^+\text{, SO}_3\text{H}^+\text{, NO}^+\text{, NO}_2^+\text{, X}^+\text{, R}^+ \text{ etc.}$ $\text{Thus, option 3 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}