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Current Question (ID: 10903)

Question:
$\text{Among the following groups maximum -I effect is exerted by:}$
Options:
  • 1. $-\text{C}_6\text{H}_5$
  • 2. $-(\text{OCH})_3$
  • 3. $-\text{Cl}$
  • 4. $-\text{NO}_2$ (Correct)
Solution:
$\text{Hint: The electronegative element or electronegative element containing group show -I effect}$ $\text{When an electronegative atom such as a halogen, oxygen, or nitrogen is introduced to a chain of atoms (generally carbon atoms), the resulting unequal sharing of electrons generates a positive charge which is transmitted through the chain.}$ $\text{This causes a permanent dipole to arise in the molecule wherein the electronegative atom holds a negative charge and the corresponding effect is called the electron-withdrawing inductive effect, or the -I effect.}$ $\text{Among all the options} - \text{NO}_2 \text{ group is the most electronegative group. Thus it will show a strong -I effect}$ $\text{The positive charge on nitrogen makes it an electron-withdrawing group. That why} - \text{NO}_2 \text{ show -I effect.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}