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Current Question (ID: 10905)

Question:
$\text{The most stable carbocation among the following is:}$
Options:
  • 1. $(CH_3)_3C^+CHCH_3$
  • 2. $CH_3CH_2CH^+CH_2CH_3$
  • 3. $(CH_3)_2CCH_2CH_2CH_3^+$ (Correct)
  • 4. $CH_3CH_2CH_2CH_2^+$
Solution:
$\text{Hint: Stability of carbocation is explained by hyperconjugation.}\n\n\text{Explanation:}\n\n\text{As the number of alpha hydrogen increases, the hyperconjugation structures are increases and the stability of carbocation also increases.}\n\n\text{The structures are as follows:}\n\n\text{Option 1: 3 alpha hydrogens}\n\text{Option 2: 4 alpha hydrogens}\n\text{Option 3: 8 alpha hydrogens}\n\text{Option 4: Least substituted primary carbocation, least stable}\n\n\text{Greater the number of hyperconjugation structures, more is the stability of the carbocation.}\n\n\text{Hence, option 3 is the correct answer.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}