Import Question JSON

Current Question (ID: 10908)

Question:
$\text{Compare the stability of the two resonating structures given below and mark the correct option:}$ $\text{H}_3\text{C}=\text{C}-\text{C}=\text{O} \leftrightarrow \text{H}_3\text{C}^+-\text{C}=\text{C}-\text{O}^-$ $\text{(I)} \hspace{50pt} \text{(II)}$
Options:
  • 1. $\text{(I) is more stable than (II)}$ (Correct)
  • 2. $\text{(II) is more stable than (I)}$
  • 3. $\text{(I) and (II) both have the same stability}$
  • 4. $\text{None of the above}$
Solution:
$\text{Hint: Neutral molecule is always stable than a charged molecule.}$ $\text{Resonance structures are a set of two or more Lewis structures that collectively describe the electronic bonding a single polyatomic species including fractional bonds and fractional charges.}$ $\text{The structure having more covalent bonds in a resonating structure has more stability. Further, there is a charge separation in structure (II) and the terminal carbon has only a sextet of electrons in (II). These two factors makes structure (II) less stable.}$ $\text{CH}_2=\text{CH}-\text{CH}=\text{O} \leftrightarrow \text{CH}_2-\text{CH}=\text{CH}-\text{O}^-$ $\text{I} \hspace{50pt} \text{II}$ $\text{Hence, I>II in terms of stability.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}