Import Question JSON

Current Question (ID: 10909)

Question:

$\text{The carbocation among the following that doesn't get stabilized by resonance is:}$

Options:

1. $\text{Cyclohexyl ring with a double bond and a positive charge at the allylic position}$
2. $\text{Allylic carbocation with a double bond adjacent to the positive charge}$
3. $\text{Carbocation with an adjacent oxygen atom having a lone pair to stabilize the positive charge}$
4. $\text{Carbocation with a double bond not adjacent to the positive charge}$ (Correct)

Solution:

$\text{Hint: Positive charge must be present at the alpha carbon of a doubly bonded carbon.}\n\n\text{The electrons can be moved in one of the following ways:}\n1.\ \text{Move } \pi \text{ electrons toward a positive charge or toward a } \pi \text{ bond.}\n2.\ \text{Move lone pair electrons toward a } \pi \text{ bond.}\n3.\ \text{Move a single non-bonding electron towards a } \pi \text{ bond.}\n\n\text{The resonance structures are as follows:}\n\n\text{Option 1: The positive charge is in the allylic position, allowing resonance stabilization through the } \pi \text{ bond.}\n\text{Option 2: The allylic carbocation is stabilized by resonance with the adjacent double bond.}\n\text{Option 3: The oxygen atom donates its lone pair to stabilize the positive charge via resonance.}\n\n\text{In option 4, resonance does not take place because the positive charge is not present at the adjacent carbon of the double bond.}\n\n\text{Therefore, the correct answer is option 4.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}