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Current Question (ID: 10910)

Question:

$\text{Arrange the following groups in order of decreasing -I (inductive) effect:}$ $\text{NO}_2, \text{C}(\text{CH}_3)_3, \text{CH}_3, \text{OCH}_3, \text{Br}$

Options:

1. $\text{NO}_2 > \text{Br} > \text{OCH}_3 > \text{C}(\text{CH}_3)_3 > \text{CH}_3$
2. $\text{NO}_2 > \text{Br} > \text{OCH}_3 > \text{CH}_3 > \text{C}(\text{CH}_3)_3$ (Correct)
3. $\text{NO}_2 > \text{OCH}_3 > \text{Br} > \text{C}(\text{CH}_3)_3 > \text{CH}_3$
4. $\text{NO}_2 > \text{OCH}_3 > \text{C}(\text{CH}_3)_3 > \text{Br} > \text{CH}_3$

Solution:

$\text{Hint: More electronegative group shows more strong -I effect.}$ $\text{When an electronegative atom or group is attached to a chain of atoms (generally carbon atoms), the resulting unequal sharing of electrons generates a positive charge which is transmitted through the chain.}$ $\text{This causes a permanent dipole to arise in the molecule wherein the electronegative atom holds a negative charge and the corresponding effect is called the electron-withdrawing inductive effect, or the -I effect.}$ $\text{The higher the electronegativity, the higher is the -I effect}$ $\text{NO}_2 > \text{Br} > \text{OR} > \text{R}$ $\text{Hence, the second option is the correct.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}