Import Question JSON

Current Question (ID: 10912)

Question:

$\text{Which of the following carbon marked with asterisk is expected to have greatest positive charge?}\n\text{1. } {*}\text{CH}_3 - \text{CH}_2 - \text{Cl}\n\text{2. } {*}\text{CH}_3 - \text{CH}_2 - \text{Mg}^{+}\text{Cl}^{-}\n\text{3. } {*}\text{CH}_3 - \text{CH}_2 - \text{Br}\n\text{4. } {*}\text{CH}_3 - \text{CH}_2 - \text{CH}_3$

Options:

1. ${*}\text{CH}_3 - \text{CH}_2 - \text{Cl}$ (Correct)
2. ${*}\text{CH}_3 - \text{CH}_2 - \text{Mg}^{+}\text{Cl}^{-}$
3. ${*}\text{CH}_3 - \text{CH}_2 - \text{Br}$
4. ${*}\text{CH}_3 - \text{CH}_2 - \text{CH}_3$

Solution:

$\text{Hint: consider inductive effect of substituents}\n\n\text{Electronegativity of Cl, Br, C and Mg follows the order Cl > Br > C > Mg.}\n\n\text{1. } {*}\text{CH}_3 \rightarrow \text{CH}_2 \rightarrow \text{Cl } (-I\text{ - effect})\n\text{2. } {*}\text{CH}_3 \leftarrow \text{CH}_2 \leftarrow \text{Mg}^{+}\text{Cl}^{-} \n\text{3. } {*}\text{CH}_3 \rightarrow \text{CH}_2 \rightarrow \text{Br } (-I\text{ - effect})\n\text{4. } {*}\text{CH}_3 \leftarrow \text{CH}_2 \leftarrow \text{CH}_3 \ (+I\text{ - effect})\n\n\text{The } -I\text{ effect of } \text{Cl} \text{ is greater than that of } \text{Br}.\n\n\text{A greater negative inductive effect (-I effect) pulls electron density away from the carbon atom, increasing its positive charge.}\n\n\text{Therefore, } {*}\text{CH}_3 - \text{CH}_2 - \text{Cl} \text{ has the greatest positive charge on the carbon atom with the asterisk.}\n\n\text{Thus, the correct answer is option 1.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}