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Current Question (ID: 10914)

Question:
$\text{The resonance hybrid structure will not exist for-}\n\text{a. } \text{CH}_3\text{OH}\n\text{b. } \text{R - CONH}_2\n\text{c. } \text{CH}_3\text{CH} = \text{CHCH}_2\text{NH}_2$
Options:
  • 1. $\text{a, and c}$ (Correct)
  • 2. $\text{a, and b only}$
  • 3. $\text{only a}$
  • 4. $\text{b and c only}$
Solution:
$\text{Hint: Application of resonance}\n\text{Explanation:}\n\text{Step 1: Find out the resonance}\text{a) } \text{CH}_3\text{OH} \text{ as it lacks pi-electrons hence it will not exist as a resonance hybrid.}\n\n\text{b) } \text{R - CONH}_2 \text{ due to the presence of n-electrons on N and pi electrons on C=O bond, hence amide can be represented as a resonance.}\n\n\text{c) } \text{CH}_3\text{CH} = \text{CHCH}_2\text{NH}_2 \text{ as the lone pair of electrons on the N- atom is not conjugated with the pi-electrons of double bond.}\n\n\text{Step 2: } \text{CH}_3\text{OH} \text{ and } \text{CH}_3\text{CH}=\text{CHCH}_2\text{NH}_2 \text{ will not show resonance}\n\n\text{Hence, the correct answer is option 1.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}