Import Question JSON

Current Question (ID: 10915)

Question:

$\text{The correct order of decreasing stability of the following carbocations is:}$

Options:

1. $$\text{II} > \text{I} > \text{III}$$ (Correct)
2. $$\text{I} > \text{II} > \text{III}$$
3. $$\text{II} < \text{I} < \text{III}$$
4. $$\text{I} < \text{II} < \text{III}$$

Solution:

$\text{Hint: Electron donating group stabilizes the carbocation.}\n\n\text{The stability of given cations can be understood by the following structures.}\n\n\text{I. } \text{CH}_3\text{ - } \overset{\oplus}{\text{CH}} \text{ - } \text{CH}_3 \\ \text{ Weak } +\text{I}\text{-effect of the two methyl groups stabilises carbocation (I)}\n\n\text{II. } \text{CH}_3\text{ - } \overset{\oplus}{\text{CH}} \text{ - } \text{OCH}_3 \\ \text{ Strong } +\text{R}\text{-effect of the -OCH}_3 \text{ group stabilises carbocation (II)}\n\n\text{III. } \text{CH}_3\text{ - } \overset{\oplus}{\text{CH}} \text{ - } \text{CH}_2 \text{ - } \text{OCH}_3 \\ \text{ -I}\text{-effect of } -\text{OCH}_3 \text{ group destabilises the carbocation (III)}\n\n\text{The second carbocation is stabilized by the mesomeric effect of oxygen. The first carbocation is stabilized by the inductive effect of two methyl groups. The third carbocation is destabilized by the -I effect of the oxygen atom.}\n\n\text{Hence, the decreasing order of stability of carbocation is II > I > III.}\n\n\text{Therefore, option 1 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}