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Current Question (ID: 10919)

Question:
$\text{The most stable canonical structure among the given structures is/are:}$
Options:
  • 1. $\text{I}$
  • 2. $\text{II}$
  • 3. $\text{III}$ (Correct)
  • 4. $\text{All are equally stable}$
Solution:
$\text{Hint: An atom with an incomplete octet is less stable than an atom with complete octet.}$ $\text{The features that decrease the predicted stability of a contributing resonance structure are as follows:}$ $\text{1. An atom with an incomplete octet}$ $\text{2. A negative charge that is not on the most electronegative atom or a positive charge that is not on the least electronegative atom}$ $\text{3. Charge separation}$ $\text{Analysis of the structures:}$ $\text{Structure I: Has charge separation with negative charge on carbon and positive charge on oxygen}$ $\text{Structure II: Has charge separation with positive charge on carbon and negative charge on oxygen}$ $\text{Structure III: All atoms have complete octets with no charge separation}$ $\text{In the third structure, all atoms have a complete octet. But in the first and second structures, all atoms do not have a complete octet. Hence, the third structure is the most stable structure.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}