Import Question JSON

Current Question (ID: 10923)

Question:

$\text{Which one of the following has the most acidic nature?}$

Options:

1. $\text{Benzyl alcohol (C}_6\text{H}_5\text{CH}_2\text{OH)}$
2. $\text{Phenol (C}_6\text{H}_5\text{OH)}$ (Correct)
3. $\text{Cyclohexanol (C}_6\text{H}_{11}\text{OH)}$
4. $\text{Dicyclohexylmethanol}$

Solution:

$\text{Hint: The presence of electron-withdrawing substituent increases the acidity while electron releasing substituent decreases the acidity}$ $\text{Step 1:}$ $\text{The acidity of a compound depends on two factors which are given below:}$ $\text{(a) pKa value is inversely proportional to acidity}$ $\text{(b) Resonance of anion will increase the stability of anion hence acidity will increase.}$ $\text{Step 2:}$ $\text{The conjugate base of phenol is highly stable due to the resonance effect. The phenoxide ion can delocalize its negative charge through the benzene ring via resonance structures.}$ $\text{In contrast, the other alcohols (benzyl alcohol, cyclohexanol, and dicyclohexylmethanol) do not have this resonance stabilization of their conjugate bases.}$ $\text{Hence the answer is option 2.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}