Import Question JSON

Current Question (ID: 10926)

Question:

$\text{The aromatic structure(s) out of given structures is/are:}$

Options:

1. {A, C, D, F & G only}
2. {A & D only}
3. $\text{A, C, E, F only}$ (Correct)
4. $\text{All are aromatic}$

Solution:

$\text{Hint: Follow Hückel's Rule for Aromaticity}$ $\text{Step 1: Follow these points on each above molecules systematically}$ $\text{Compound A (Pyridine): Planar ring - Yes, Complete delocalization of π-electron - Yes, 6πe⁻ - Hückel rule obeyed, Aromatic}$ $\text{Compound B (Cycloheptatriene): Planar ring - No, Complete delocalization - No, Incomplete (sp³ hybrid carbon), 6πe⁻ - Non-aromatic}$ $\text{Compound C (Cyclopentadienyl anion): Planar ring - Yes, Complete delocalization - Yes, 6πe⁻ (4n+2+lone pair e⁻) Hückel rule verified, Aromatic}$ $\text{Compound D (Cyclopentenyl cation): Planar ring - Yes, Complete delocalization - No, 4πe⁻ - Anti-aromatic}$ $\text{Compound E (Tropylium cation): Planar ring - Yes, Complete delocalization - Yes, Hückel rule obeyed, Aromatic}$ $\text{Compound F (Cyclopropenyl cation): Planar ring - Yes, Complete delocalization - Yes, 2πe⁻ Hückel rule verified n=0, Aromatic}$ $\text{Compound G (Cyclooctatriene): Planar ring - Yes, Complete delocalization - No, 8πe⁻ Hückel rule not verified, Non-aromatic}$ $\text{Step 2: Hence those molecules which follow Hückel's rule, planarity according to the 4n+2 π-electron rule, are aromatic.}$ $\text{Therefore, compounds A, C, E, and F are aromatic.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}