Import Question JSON

Current Question (ID: 10943)

Question:

$\text{Match the type of mixture of compounds in Column I with the technique of separation/purification given in Column II.}$ $\text{Column I:}$ $\text{A. Two solids which have different solubilities in a solvent and which do not undergo a reaction when dissolved in it}$ $\text{B. Liquid that decomposes at its boiling point}$ $\text{C. Steam volatile liquid}$ $\text{D. Two liquids that have boiling points close to each other}$ $\text{Column II:}$ $\text{1. Steam distillation}$ $\text{2. Fractional distillation}$ $\text{3. Crystallisation}$ $\text{4. Distillation under reduced pressure}$

Options:

1. $\text{A-3, B-4, C-1, D-2}$ (Correct)
2. $\text{A-1, B-2, C-3, D-4}$
3. $\text{A-1, B-4, C-3, D-2}$
4. $\text{A-4, B-1, C-3, D-2}$

Solution:

$\text{Hint: Purification method}$ $\text{The correct matching is based on the principle of each purification technique:}$ $\text{A. Two solids with different solubilities → Crystallisation (3)}$ $\text{The solid with higher solubility can be separated from the one with lower solubility using crystallisation technique.}$ $\text{B. Liquid that decomposes at its boiling point → Distillation under reduced pressure (4)}$ $\text{When a liquid decomposes at its normal boiling point, distillation under reduced pressure allows it to boil at a lower temperature, preventing decomposition.}$ $\text{C. Steam volatile liquid → Steam distillation (1)}$ $\text{Steam distillation is specifically used for separating steam volatile organic compounds that are immiscible with water.}$ $\text{D. Two liquids with boiling points close to each other → Fractional distillation (2)}$ $\text{When two liquids have similar boiling points, simple distillation is not effective, so fractional distillation with a fractionating column is used.}$ $\text{Therefore, the correct matching is A-3, B-4, C-1, D-2.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}