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Current Question (ID: 10944)

Question:

$\text{If a liquid compound decomposes at or below its boiling point, then the best method for purification is-}$

Options:

1. $\text{Distillation under reduced pressure}$ (Correct)
2. $\text{Azeotropic distillation}$
3. $\text{Gas chromatography}$
4. $\text{Sublimation}$

Solution:

$\text{Hint: Distillation under reduced pressure}$ $\text{Explanation:}$ $\text{It is a process that is performed under reduced pressure and separates compounds based on differences in their boiling points. The pressure is reduced here because it helps in decreasing the boiling point of the compound.}$ $\text{The compounds that boil beyond their decomposition temperature at atmospheric pressure and can be easily distilled under the atmospheric pressure without being decomposed are also separated using vacuum distillation.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}