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Current Question (ID: 10947)

Question:
$\text{The latest technique for isolation, purification and separation of organic compounds is -}$
Options:
  • 1. $\text{Crystallisation}$
  • 2. $\text{Distillation}$
  • 3. $\text{Sublimation}$
  • 4. $\text{Chromatography}$ (Correct)
Solution:
$\text{Hint: The technique contains the mobile phase and stationary phase.}$ $\text{Chromatography is the most useful and the latest technique of separation and purification of organic compounds. It was first used to separate a mixture of colored substances.}$ $\text{To get the process started, the mixture is dissolved in a substance called the mobile phase, which carries it through a second substance called the stationary phase.}$ $\text{The different components of the mixture travel through the stationary phase at different speeds, causing them to separate from one another.}$ $\text{Key advantages of chromatography:}$ $\text{• Precise separation, analyses, and purification is possible using chromatography.}$ $\text{• It requires very low sample volumes.}$ $\text{• It works on a wide range of samples including drugs, food particles, plastics, pesticides, air and water samples, and tissue extracts.}$ $\text{• Mixture components separated by chromatography can be collected individually.}$ $\text{• It can be used to separate highly complex mixtures.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}