Import Question JSON

Current Question (ID: 10948)

Question:
$\text{The method that can be used to separate two compounds with different solubilities in a solvent is-}$
Options:
  • 1. $\text{Distillation}$
  • 2. $\text{Isolation}$
  • 3. $\text{Fractional crystallization}$ (Correct)
  • 4. $\text{Filtration}$
Solution:
$\text{Hint: Fractional crystallisation is the method used for separating two compounds with different solubilities in a solvent.}$ $\text{Step 1:}$ $\text{The process of fractional crystallization is carried out in four steps.}$ $\text{(a) Preparation of the solution: The powdered mixture is taken in a flask and the solvent is added to it slowly and stirred simultaneously. The solvent is added till the solute is just dissolved in the solvent. This saturated solution is then heated.}$ $\text{(b) Filtration of the solution: The hot saturated solution is then filtered through a filter paper in a China dish.}$ $\text{Step 2:}$ $\text{(c) Fractional crystallization: The solution in the China dish is now allowed to cool. The less soluble compound crystallizes first, while the more soluble compound remains in the solution. After separating these crystals from the mother liquor, the latter is concentrated once again. The hot solution is allowed to cool and consequently, the crystals of the more soluble compound are obtained.}$ $\text{(d) Isolation and drying: These crystals are separated from the mother liquor by filtration. Finally, the crystals are dried.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}