Import Question JSON

Current Question (ID: 10950)

Question:

$\text{The purification method based on the difference in solubilities of the compound and the impurities in a solvent is -}$

Options:

1. $\text{Crystallisation}$ (Correct)
2. $\text{Distillation}$
3. $\text{Chromatography}$
4. $\text{Isolation}$

Solution:

$\text{Hint: Crystallisation is one of the most commonly used techniques for the purification of solid organic compounds.}$ $\text{Step 1: Crystallization}$ $\text{Principle: It is based on the difference in the solubilities of the compound and the impurities in a given solvent.}$ $\text{The impure compound gets dissolved in the solvent in which it is sparingly soluble at room temperature but appreciably soluble at higher temperatures. The solution is concentrated to obtain a nearly saturated solution. On cooling the solution, the pure compound crystallises out and is removed by filtration.}$ $\text{Step 2:}$ $\text{(b) Distillation}$ $\text{This method is used to separate volatile liquids from non-volatile impurities or a mixture of liquids with a sufficient difference in their boiling points.}$ $\text{(c) Chromatography}$ $\text{Principle: It is based on the difference in movement of individual components of a mixture through the stationary phase under the influence of mobile phase.}$ $\text{Hence, option 1 is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}