Import Question JSON

Current Question (ID: 10963)

Question:

$\text{In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. The percentage of sulphur in the compound is-}$

Options:

1. $39.10\%$
2. $48.13\%$
3. $42.10\%$ (Correct)
4. $52.43\%$

Solution:

$\text{Hint: Percentage of sulphur} = \frac{32 \times m_1 \times 100}{233 \times m}$ $\text{Step 1:}$ $\text{Molecular mass of } \text{BaSO}_4 = 137 + 32 + 64 = 233 \text{ g}$ $233 \text{ g } \text{BaSO}_4 \text{ contains } 32 \text{ g sulphur}$ $0.4813 \text{ g } \text{BaSO}_4 \text{ contains } \frac{32}{233} \times 0.4813 \times 233 \text{ g sulphur}$ $\text{Step 2:}$ $\text{Calculate the percentage of sulphur as follows:}$ $\text{Percentage of sulphur} = \frac{32}{233} \times 0.4813 \times \frac{100}{0.157} = 42.10\%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}