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Current Question (ID: 10965)

Question:

$\text{Silver sulphate solution is used to separate:}$

Options:

1. $\text{Nitrate and bromide}$ (Correct)
2. $\text{Nitrate and chlorate}$
3. $\text{Bromide and iodide}$
4. $\text{Nitrate and nitrite}$

Solution:

$\text{Hint: Bromide ion form precipitate with silver sulphate}$ $\text{When silver sulphate solution adds to the solution which contains bromide and nitrate ion then bromide ion and nitrate ion are easily separated.}$ $\text{The bromide ion reacts with } \text{Ag}^+ \text{ ion and forms a precipitate of } \text{AgBr}\text{. But nitrate ion } (\text{NO}_3^-) \text{ with } \text{Ag}^+ \text{ and form a soluble compound. Hence nitrate ions remain in the solution and bromide ions precipitate in the form of } \text{AgBr}\text{.}$ $\text{The reaction is as follows:}$ $\text{Ag}^+(\text{aq}) + \text{Br}^-(\text{aq}) \rightarrow \text{AgBr}(\text{s})$ $\text{Ag}^+(\text{aq}) + \text{NO}_3^- \rightarrow \text{AgNO}_3(\text{aq})$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}