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Current Question (ID: 10966)

Question:

$\text{Soda extract is prepared by-}$

Options:

1. $\text{Fusing soda and mixture of hydrocarbons, and then extracted with water}$
2. $\text{Dissolving NaHCO}_3 \text{ and mixture of hydrocarbons in dil. HCl}$
3. $\text{Boiling Na}_2\text{CO}_3 \text{ and mixture of hydrocarbons in dil. HCl}$
4. $\text{Boiling Na}_2\text{CO}_3 \text{ and mixture of hydrocarbons in distilled water}$ (Correct)

Solution:

$\text{Hint: The process to prepare soda extract is as follows:}$ $\text{To prepare soda extract, mixture/salt is mixed with pure Na}_2\text{CO}_3 \text{ in 1:2 ratio and a sufficient amount of water are added. The whole content is boiled for 15-20 minutes and then filtered. The filtrate is used as soda extract.}$ $\text{The reaction is as follows:}$ $\text{MA}_2 + \text{Na}_2\text{CO}_3 \rightarrow \text{MCO}_3 + 2\text{NaA}$ $\text{Ca}_3(\text{PO}_4)_2 + 3\text{Na}_2\text{CO}_3 \rightarrow 3\text{CaCO}_3 + 2\text{Na}_3\text{PO}_4$ $\text{CaC}_2\text{O}_4 + \text{Na}_2\text{CO}_3 \rightarrow \text{CaCO}_3 + \text{Na}_2\text{C}_2\text{O}_4 \text{ (Water soluble)}$ $\text{PbSO}_4 + \text{Na}_2\text{CO}_3 \rightarrow \text{PbCO}_3 \downarrow + \text{Na}_2\text{SO}_4 \text{ (Water soluble)}$ $\text{(a) Some cations interfere in the confirmatory test of some anions when present in solution. Such cations are eliminated in the form of insoluble carbonates as a result of treatment with sodium carbonate.}$ $\text{(b) It becomes easier to identify anions in such mixture which are insoluble in water and dil. acids.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}