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Current Question (ID: 10967)

Question:

$\text{In Kjeldahl's method of estimation of nitrogen, } \text{K}_2\text{SO}_4 \text{ acts as:}$

Options:

1. $\text{An oxidizing agent}$
2. $\text{A catalytic agent}$
3. $\text{A hydrolyzing agent}$
4. $\text{A boiling point elevator}$ (Correct)

Solution:

$\text{Hint: On adding salt boiling point increased.}$ $\text{In Kjeldahl's method, the acid breaks down the organic substance via oxidation and reduced nitrogen in the form of ammonium sulphate. Potassium sulphate is usually added to increase the boiling point of the } \text{H}_2\text{SO}_4 \text{ and } \text{CuSO}_4 \text{ or Hg acts as a catalyst.}$ $\text{The reaction is as follows:}$ $\text{Organic compound} + \text{H}_2\text{SO}_4 \rightarrow [\text{digest}]\text{Cu}^{2+} + (\text{NH}_4)_2\text{SO}_4$ $\text{For compounds containing nitrogen in azo and nitro groups or in rings (quinoline, pyridine, etc.), in these cases, the nitrogen cannot be converted to ammonium sulphate by following the Kjeldahl method.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}