Import Question JSON

Current Question (ID: 10968)

Question:

$\text{In an estimation of sulphur by the carius method, 0.2175 g of the substance gave 0.5825 g of BaSO}_4\text{. The percentage composition of S in the compound is-}$

Options:

1. $66\%$
2. $20\%$
3. $37\%$ (Correct)
4. $82\%$

Solution:

$\text{Hint: Percentage of sulphur} = \frac{32 \times m_1 \times 100}{233 \times m}$ $\text{Step 1:}$ $\text{The weight of the organic compound is 0.2175 g}$ $\text{The weight of BaSO}_4 \text{ is 0.5825 g}$ $\text{233 g of BaSO}_4 \text{ contains 32 g of S}$ $\text{0.5825 g of BaSO}_4 \text{ contains } \frac{32}{233} \times \frac{0.5825}{0.2175}$ $\text{Step 2:}$ $\text{Percentage of S} = \frac{32}{233} \times \frac{0.5825}{0.2175} \times 100 = 36.78\%$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}